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(A) The substrate is $1$-bromo-$1,2$-dimethylcyclohexane. When treated with a bulky base like potassium $tert$-butoxide $(t-BuOK)$,the $E_2$ eliminati

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$1-$methyl$-2-$methylenecyclohexane

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(A) The substrate is $1$-bromo-$1,2$-dimethylcyclohexane. When treated with a bulky base like potassium $tert$-butoxide $(t-BuOK)$,the $E_2$ elimination reaction occurs.$t-BuOK$ is a sterically hindered base,which prefers to abstract a proton from the less sterically hindered position (Hofmann product).In this molecule,there are two types of $\beta$-hydrogens available for elimination:$1$. Protons on the $CH_2$ group of the ring (leading to the more substituted,Zaitsev product,$1,2$-dimethylcyclohex-$1$-ene).$2$. Protons on the exocyclic $CH_3$ group attached to the $C_1$ position or the $CH_2$ group adjacent to $C_1$ (leading to the less substituted,Hofmann product,$1$-methyl-$2$-methylenecyclohexane).Due to the steric bulk of the $t-BuOK$ base,it preferentially abstracts the more accessible proton from the $CH_2$ group adjacent to the $C_1$ position to form the less substituted alkene,which is $1$-methyl-$2$-methylenecyclohexane.

The major product obtained when this substrate is subjected to $E_2$ reaction under the treatment of potassium $tert$-butoxide is:

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